The Wowo Novelty Company makes three basic types of noisemakers: Toot, Wheet and honk. A toot can be made in 30 minutes and has a feather attached to it. A wheet requires 15 minutes, has two feathers and is sprinkled with 0.5 oz of sequin powder. A honk requires 30 minutes, has 3 feathers and 1 oz of sequin powder. The net profit is P0.40 per toot, P0.5 per wheet and P0.80 per honk. The following resources are available: 80 hours of labor, 360 feathers and 90 oz of sequin powder. Determine the quantity of each type of noisemakers that maximizes profit.

P104

Step-by-step explanation:

Let x represent the number of toot, y represent the number of wheet and z represent the number of honk.

Since a toot is made in 30 minutes (0.5 hours), wheet in 15 minutes (0.25 hour), honk in 30 min (0.5 hr). There is 80 hours of labor, hence:

0.5x + 0.25y + 0.5z ≤ 80     (1)

There are 360 feathers, hence:

x + 2y + 3z ≤ 360      (2)

There is 90 oz of powder, hence:

0.5y + z ≤ 90    (3)

solving equation 1, 2 and 3, gives:

x = 70, y= 40, z = 70

The profit is given by:

Profit = 0.4x + 0.5y + 0.8z

substituting x, y and z gives:

Profit = 0.4(70) + 0.5(40) + 0.8(70) = P104

the answer is c)8

step-by-step explanaction:

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

pls mark as brainliest