Find the lettered angles in each of the following. ( where a point o is given , it is the centre of the circle) .​

q = 80 degrees

r = 70 degrees

s = 10 degrees

t = 70 degrees

u = 40 degrees

v = 60 degrees

Step-by-step explanation:

starting with the fact that all angles in any triangle always sum up to 180 degrees :

q = 180 - 60 - 40 = 80 degrees

r = 180 - (60+10) - 40 = 180 - 70 - 40 = 70 degrees

the triangle 40-60-q and v-u-blank are similar triangles. your can say the smaller triangle is just a projection of the large triangle through the focal point at angle q.

that means the angles must be equal.

v = 60 degrees

u = 40 degrees

similar for 10-r-blank and t-s-blank.

s = 10 degrees

t = 70 degrees

u=60°

v=40°

q=80°

r=70°

s=70°

t=10°

Solution given:

t=10°[inscribed angle on a same chord or arc is equal]

V=40°[inscribed angle on a same chord or arc is equal]

u=60°[inscribed angle on a same chord or arc is equal]

AGAIN;

40+60+10+r=180°[sum of interior angle of triangle]

r+110°=180°

r=180°-110°

r=70°

again

r=s=70°[inscribed angle on a same chord or arc is equal]

again

q=r+10°[exterior angle is equal to the sum of two opposite interior angle]

q=70+10=80°

$32,660

step-by-step explanation:

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation: