Help please 50 points!​

A and B

Step-by-step explanation:

we would like to solve the following equation:

to do so isolate -x to the left hand side and change its sign:

simplify addition:

square both sides:

simplify square of the right hand side:

use (a-b)²=a²-2ab+b² to expand the left hand side:

swap the equation:

isolate the right hand side expression to the left hand side and change every sign:

simplify:

rewrite the middle term as 13x-2x:

factor out x:

factor out -2:

group:

by Zero product property we obtain:

solve for x:

to check for extraneous solutions we can define the domain of equation recall that a square root of a function is always greater than or equal to 0 therefore

solve the inequality for x:

since 2 and -13 is less than 5 both solutions are valid for x hence,

and we're done!

x=-13

x=2

Solution given:

5-2x=

keep square root alone

5-2x+x=

5-x=

squaring both side

(5-x)²=2x²+x-1

25-10x+x²=2x²+x-1

2x²+x-1-25+10x-x²=0

x²+11x-26=0

doing middle term factorisation

for this

coefficient of first and last terms should be multiplied

here

1*26=26

factor product

26=2*13*1

remember that check the sigh of last term

in here it is - so

we need to get 11 by subtracting factor of 26

we get

13-2=11

keep 13-2 value in place of 11

x²+(13-2)x-26

now

distribute

x²+13x-2x-26=0

take common from each two term

x(x+13)-2(x+13)=0

(x+13)(x-2)=0

either

x=-13

or.x=2

step-by-step explanation:

the answer is ! ?