What is the area of a hexagon with an apothem of 24 m?

Area of Hexagon = 1,995 m² (Approx.)

Step-by-step explanation:

Given:

Length of apothem = 24 m

Number of total sides = 6

Find:

Area of Hexagon

Computation:

Side = a[2tan(180/n)]

Side = 24[2tan(180/6)]

Side = 24[2tan(30)]

Side = 27.71 m (Approx.)

Area of Hexagon = [3√3a²]/2

Area of Hexagon = [3(1.732)(27.71)²]/2

Area of Hexagon = [3(1.732)(767.8441)]/2

Area of Hexagon = 3989.71794 / 2

Area of Hexagon = 1994.8589

Area of Hexagon = 1,995 m² (Approx.)

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source