a student estimates the length of a room to be 20 feet. The actual length is 20.25 feet. What is the percent error?

Percent error=1.23%

Step-by-step explanation:

We are given that

Estimate length of room=20 feet

Actual length of room=20.25 feet

We have to find the percent error.

To find the percent error we will find the difference between the estimate length and actual length of room.

Difference=Actual length of room-Estimate length of room

Difference=20.25-20

Difference=0.25 feet

Now,

Percent error=

Percent error=

Percent error=1.23%

look in attachments

step-by-step explanation:

a = (-2, 0)

b= (-4, 0)

c = (-5,2)

d = (-1,2)

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.