Nine children are to be divided into an A team, a B team and a C team of 3 each. The A team will play in one league, the B team in another, the C team in a third league. How many different divisions are possible

The answer is "840".

Step-by-step explanation:

Following are the number of ways in which selecting a team A  by 9 children:

Following are the number of ways in which selecting a team B  by remaining 6 children:

Following are the number of ways in which selecting a team C  by remaining 3 children:

Following are the number of ways in which making 3 teams by 9 children:

(Note: we've split by 3! Because it also is necessary to implement three teams between themselves)

Now 3 leagues have to be played. One is going to be run by each team.

That is the way it is

Different possible divisions

answer: it is 1: 47 pm

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.