According to the rational root theorem which of the following are possible roots for the function below x^4-29x^2+100

Hello,

The rational roots may be all divisors of 100

+1,-1,+2,-2,+4,-4,+5,-5,+10,-10,+20,-20,+25,-25,+50,-50,+100,-100

f(x)=x^4-29x^2+100

f(5)=5^4-29*5^2+100=0 : 5 is a root

f(-5)=(-5)^4-29*(-5)²+100=0 : -5 is a root

f(2)=2^4-29*2²+100=0 : 2 is a root

f(-2)=(-2^)^4-26*(-2)²+100= 0 : -2 is the last root.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐