A. Verify that y1=e^x and y2=xe^x are solutions of y"-2y'-y=0 on (-infinity, infinity) b. Verify that if c1 and c2 are arbitrary constants then y=e^x(c1+c2x) is a solution of A on (-infinity, infinity)
c. Solve the initial value problem y"-2y'-y=0 y(0)=y y'(0)=4
s. Solve the initial value problem y"-2y'-y=0 y(0)=k0 y'(0)=k1

Whats the name of the vertical axis

Which function has the domain x> -11

How does the graph of g(x)=⌊x⌋−3 differ from the graph of f(x)=⌊x⌋? the graph of g(x)=⌊x⌋−3 is the graph of f(x)=⌊x⌋ shifted right 3 units. the graph of g(x)=⌊x⌋−3 is the graph of f(x)=⌊x⌋ shifted up 3 units. the graph of g(x)=⌊x⌋−3 is the graph of f(x)=⌊x⌋ shifted down 3 units. the graph of g(x)=⌊x⌋−3 is the graph of f(x)=⌊x⌋ shifted left 3 units.