How many distinct ways can the word EVANESCENCE be arranged if the anagram must end with the letter E? hint... 10!/2!3!2! = 151,200

151200

Step-by-step explanation:

We can start by essentially taking off the E at the end, meaning that we want to find all the combinations of

EVANESCENC. We can do this because the combinations will have an E at the end by default.

To solve this, we have to figure out the amount of letters and the amount of each letter. There are 10 letters, with 3 E's, 2 C's, 2 N's, 1 S, 1 V, and 1 A. Using the formula , with n representing the amount of letters and each subset of n representing the amount of each letters, our answer is

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

stops on an even number.