In the perfect square x^2+bx+c, why is the relationship between b and c C=(b/2)^2? Would the strategy work even if b is a negative? Also, would it work if b was an odd number? What would happen to c if b was odd?

me. I think you have to multiply so that you get the answer

Step-by-step explanation:

c = (b/2)² because b = 2c

If b is negative, then c = (-b/2)² , and x² - bx + c = (x-c)²

If b is an odd number, then c will be a fraction.

statement #3: proof- ang is congruent to ang ecd : angles are congruent.  

step-by-step explanation:

1: the missing angles in statement #3  

a.) acb  

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.  

2: the missing word in reason #3  

c.) vertical  

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.  

i hope that was and understanding.