The coordinator of the vertices of the triangle are (-8,8),(-8,-4), and

Answer with Step-by-step explanation:

Complete question:

The coordinates  of the vertices of the triangle are (-8,8),(-8,-4), and. Consider QR the base of the triangle. The measure of the base is b = 18 units, and the measure of the height is h = units. The area of triangle PQR is square units.

Let

P=(-8,8)

Q=(-8,-4)

QR=b=18 units

Height of triangle, h=Length of PQ

Distance formula

Using the formula

Height of triangle, h=

Area of triangle PQR=

Area of triangle PQR=

Area of triangle PQR=108 square units

Length of QR=18units

Let the coordinates of R(x,y)

  ......(1)

Using Pythagoras theorem

units

.....(2)

Subtract equation (2) from (1) we get

Using the value of y in equation (1)

Hence, the coordinate of R (10,-4) or (-26,-4).

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

3 3 6, because in every triangle the longer side is always shorter than the sum of the other two