Determine the degree of the Maclaurin polynomial required for the error in the approximation of the function at the indicatedvalue of x to be less than 0.0001.

Fifth degree polynomial

Step-by-step explanation:

Given data:

e^0.3

error = 0.0001

let the function ; f(x) = e^x

note : x = 0.3

The Maclaurin polynomial f(x) = e^x = 1 + x + x^2 / 2!  + x^3/3!  ---  + ∑ x^n/n!

= 1 + 0.3 + (0.3)^2/2! + (0.3)^3 / 3! --- +  ∑ (0.3)^n/n!

Attached below is the remaining part of the solution

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

need more information

step-by-step explanation: