The quadratic function f has a vertex at (3,4) and opens upward. The quadratic function g is shown below. Which statement is true? A. The minimum value of g is greater than the minimum value of f. B. The maximum value of g is greater than the maximum value of f. C. The minimum value of f is greater than the minimum value of g. D. The maximum value of f is greater than the maximum value of g.

The minimum value of f(x) is greater than the minimum value of g(x).

Step-by-step explanation:

Given

--- vertex of f(x)

--- g(x) equation

Required

Which of the options is true

First, we identify the vertex of g(x)

A quadratic function is represented as:

Where:

vertex

So, we have:

If , then the curve opens upward

From the question, we understand that f(x) also open upward. This means that both functions have a minimum

The minimum is the y (or k) coordinate

So, we have:

--- vertex of f(x)

--- vertex of g(x)

The minimum of both are:

----  f(x)

----  g(x)

By comparison:

Hence, f(x) has a greater minimum

the answer is d

step-by-step explanation:

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50