If <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO​

<BCO​ = <BAO​ = 20degrees

Step-by-step explanation:

If <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO​

To get <BAO and <BCO​, we need to get <AOC first.

From the figure, it can be seen that triangle ABC is an isosceles trinagle. Hence;

<BAC + <BCA + 100 = 180

Since <BAC = <BCA

<BAC + <BAC = 180 - 100

2<BAC = 80

<BAC = 80/2

<BAC = 40

Also;

<BAO = <BCO​ and <BAO = <BAC/2

<BAO = 40/2 = <BCO​

Hence <BCO​ = <BAO​ = 20degrees

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

i dont know

step-by-step explanation: