A state has a lottery game where a person picks one of the 1000 three-digit numbers between 000 and 999. The lottery selects a three-digit number at random. With a bet of $1, a person wins $700 if their number is selected and nothing ($0) otherwise. The expected value of the probability distribution for the amount of money you will win is 0.70. What is the correct interpretation of the expected value

A player can expect to win an average of 0.70 per lottery after playing the lottery sufficiently many times.

Step-by-step explanation:

The expected value for the amount of money to be won is 0.70 ;

The expected value of expected mean simply means the long run average because the expected mean refers to the average value of a random variable which is which is obtained over a large number of trials or experiment. In the case of lottery game, expected will thus be interpreted to mean the average winning (or loss) expected which a player earns or incurs after playing the lottery many times. It differs from the mean or average value earned after playing just a game or two as it refers to a long run average.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.