How do i solve this

it’s geometry

x=5, y=11

Step-by-step explanation:

> sum of interior angles of a polygon is (n-2)·180°, where n-is the number of sides, so our rhombus has sum of angles =(4-2)·180° =360°

>we know that the opposite angles are congruent so ...

>we have the sum of interior angles is

108+108+7y-5+7y-5 = 360, combine like terms

14y +206 =360, subtract 206 from both sides

14y = 154, divide both sides by 14

y= 11

>the sides are congruent therefore

4x+17 = 8x-3 , subtract 4x, and add 3 from both sides

17+3 =8x-4x, combine like terms

20 = 4x , divide by 4 both sides

5 =x

50- 250 is correct i did that one too

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!