intensity of the vector is v= β37 β 6.08 units and make angle β‘Ξ± β 9.46Β° with east direction
step-by-step explanation:
required vector is consists of the two componentsvx= 2+4=6 units and vy= 1 unit and vx β₯ vywe will use pythagorian theorem to find intensity of the vector vvβ§2 = vxβ§2 + vyβ§2 => v = βvxβ§2 + vyβ§2 = β6β§2 + 1β§2 = β36+1 = β37 β 6.08 unitsthe angle β‘Ξ± between vector and east direction we wil find with tanΞ±tanΞ± = 1/6 => Ξ± = arc tanΞ± = arc 1/6 => Ξ± β 9.46Β°
hope this