This is my last question, I hope to get the right answer
pls and ty :>

Options A ,  D , E

Step-by-step explanation:

Triangle has angles 27° and 45°

The third angle = 180 - 27 - 45 = 108°

Therefore, the angles of ABC are 27° , 45° , 108°

=> ABC is Scalene triangle .

Option A :

Triangle DEF :

       3x + 5x + 12x = 180°

              20x = 180°

               x = 9

Therefore , the angles of DEF = 27° , 45° , 108°

Satisfies

Option B:

Triangle GHI is Isosceles triangle with one angle 108°

But ABC is scalene , therefore not similar.

Does not satisfy.

Option C :

Triangle JKL with one of the angle = 72°

But none of the angles of ABC is equal to 72° .

Therefore, not similar.

Does not satisfy.

Option D :

Triangle MNO have angles 45°  and  108°.

Sum of angles of triangles = 180°

So the third angle of MNO = 27°

Therefore , MNO is similar to ABC.

Satisfy.

Option E:

Angles of triangle PQR are 45° , x° , 4x°

Lets find all the angles .

45 + x + 4x = 180°

5x = 180 - 45

5x = 135

x = 27

Therefore, the angles of PQR = 45° , 27° , 108°

Hence similar to triangle ABC.

Satisfy

Option F :

Angles of triangle STU (5x + 3)°, (9x)° , (21x + 2)°

Sum of the angles => 5x + 3 + 9x + 21x + 3 = 180°

                            => 35x = 180 - 5

                            => 35x = 175

                            => x = 5

Therefore, the angles are

5x + 3 = 5( 5) + 3 = 25 + 3 = 28°

9x =  9 ( 5 ) = 45°

21x + 2 = 21(5) + 2 = 105 + 2  = 107°

The angles are not congruent to the angles of Triangle ABC

does not satisfy.

this doesn't make sense lol