![\sqrt{x} = x^{1/2} ....... \sqrt[3]{x} = x^{1/3} \\also that (x^{a})^{b} = x^{a*b}](/tpl/images/1385/5584/50ff2.png)
Could someone please help and explain how to do this
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Mathematics, 29.06.2021 01:00, diamondscott9297
Could someone please help and explain how to do this
Answers: 2
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