Write the equation of the line that passes through the points (6,-6) and (7,-4) Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.

9514 1404 393

  y +6 = 2(x -6)

Step-by-step explanation:

The slope can be found using the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (-4 -(-6))/(7 -6) = 2/1 = 2

The point-slope equation for a line is ...

  y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

Using the slope we found and the first point, the equation is ...

  y +6 = 2(x -6)

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

it's both, now can you answer my most recent question?