Perpendicular Bisector Theorem: Theorems Distance and perpendicular Bisectors
THEOREM
HYPOTHESIS CONCLUSION
5-1-1 Perpendicular Bisector
Theorem
If a point is on the perpendicular
bisector of a segment, then it is
equidistant from the endpoints
A
XAX
B
of the segment.
XY A
YAY8
2 claus como
5-1-2 Converse of the Perpendicular
Bisector Theorem
If a point is equidistant from
the endpoints of a segment
then it is on the perpendicular
bisector of the segment.
XY A
YAY
ХАХВ
Examples:
1) YW =
2) BC
3) PR-
w
B
ts
36
P
Q
73
D
2n +9
7n - 18
16
С
36
х
R
4) Given that line I is the perpendicular bisector
of DE and EG = 14.6, then DG
5) Given that DE = 20.8, DG = 36.4, and E
EG 36.4, then EF-
.

Xto the second power plus 14x plus 48. what are the factors? we are doing factoring trinomials with a=1

To which sets of numbers does -12 belong? choose all answers that are correct. a) natural numbers b) integers c) real numbers d) irrational numbers

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.