Graph the image of square CDEF after a reflection across the x-axis​

If you have a general point (x, y), and you reflect it across the x-axis, the coordinates of the new point will be:

(x,-y)

So we only change the sign of the y-component.

Now, if we do a reflection across the x-axis of a whole figure, then we apply the reflection to all the points that make the figure.

Then, we could just apply the reflection to the vertices of the square, then graph the new vertices, and then connect them, that is equivalent to graph the image of the square after the reflection.

The original vertices are:

C = (-3, 7)

D = (0, 7)

E = (0, 10)

F = (-3, 10)

Now we apply the reflection, remember that this only changes the sign of the y-component, then the new vertices are:

C' = (-3, -7)

D' = (0, -7)

E' = (0, - 10)

F' = (0, - 10)

Now we need to graph these points and connect them to get the reflected figure, the image can be seen below.

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).