Question 7(Multiple Choice Worth 1 points) (01.07 LC) Find the measure ofx. S 15(x+2) 135° T Ox=8 Ox=7 On11​

Given:

QR and ST are parallel lines, and PU is a transversal line.

To find:

The value of x.

Solution:

If a transversal line intersect two parallel lines, then the alternate exterior angles are equal.

         (Alternate exterior angles)        

Subtracting 30 from both sides, we get

Dividing both sides, we get 15.

Therefore, the value of x is 7.

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

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