Find atleast 3 solutions for the following linear equation in two variables:2x + 3y = 4​

First solution :

Say, x = 0

→ 2x + 3y = 4

→ 2(0) + 3y = 4

→ 0 + 3y = 4

→ 3y = 4

→ y = 4/3

Second solution :

Say, x = 1

→ 2x + 3y = 4

→ 2(1) + 3y = 4

→ 2 + 3y = 4

→ 3y = 4 - 2

→ 3y = 2

→ y = 2/3

Third solution :

Say, x = 2

→ 2x + 3y = 4

→ 2(2) + 3y = 4

→ 4 + 3y = 4

→ 3y = 4 - 4

→ 3y = 0

→ y = 0 ÷ 3

→ y = 0

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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