If a line has an x-intercept at = 3 and a y-intercept at y = – 5, find its equation in the form
y = mx + b.
y

y = 5/3x - 5

Step-by-step explanation:

y = mx + b

b = y-intercept

m = slope

y = mx - 5

plug in the x-intercept

0 = m(3) - 5

5 = 3m

m = 5/3

y = 5/3x - 5

graph is below, both intercepts are on the line

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752