A line is parallel to y = 3x + 5 and intersects the point (-2 , 6). What is the equation of this parallel line?

y = 3x + 12

Step-by-step explanation:

Slope of y = 3x + 5 is 3

Line parallel will have same slope 3

Line intersects point at (-2, 6)

Replace into y = mx + b to find

6 = 3(-2) + b

6 = -6 + b

12 = b

Equation of line:

y = 3x + 12

y = 3x + 12

Step-by-step explanation:

Lines parallel to each other will have the same slope but different y-intercepts. This means that the equation of this parallel line has a slope of 3.

y = 3x + b

Now we need to find the y-intercept by plugging in the point (-2, 6) into the equation. (Replace x with -2 and y with 6.) Then we solve it.

y = 3x + b

6 = 3(-2) + b

6 = -6 + b

+6 +6

12 = b

The y- intercept is 12. So the equation of the parallel line is y = 3x + 12

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.