In what ratio of line x-y-2=0 divides the line segment joining (3,-1)and (8,9)​

The ratio in which the line x-y-2=0 divides the line joining A(3,-1) and B(8,9) is in the ratio 2:3

Step-by-step explanation:

Let (x, y) be the coordinates of point of intersection.

Hence x=(a*8+1*3)(a+1) = (8a+3)/(a+1)

and

y = {a*9+1*(-1)}/(a+1)=(9a-1)/(a+1)

Since this point lies on the line x-y-2=0

Hence (8a+3)/(a+1)-(9a-1)/(a+1)-2=0

i.e. 8a+3–9a+1–2(a+1)=0

Or 8a+3–9a+1–2a-2=0

i.e.-3a+2=0

Hence a=2/3

hence the ratio in which the line x-y-2=0 divides the line joining A(3,-1) and B(8,9) in the ratio 2/3:1

i.e. 2:3

they will manufacture 8496 cars

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,