A certain game consists of rolling a single fair die and pays off as follows: $10 for a 6, $7 for a 5, $4 for a 4, and no payoff otherwise, Find the expected winnings for this game.
The expected winnings for this game are
(Round to the nearest hundredth.)
1
m
21
m
se
?
Enter your answer in the answer box.

$3.50

Step-by-step explanation:

Given:

$10 for a 6, $7 for a 5, $4 for a 4, and no payoff otherwise

P(6) = 1/6 ; p(5) = 1/6 ; p(4) = 1/6 ; p(1,2or3) = 3/6 = 1/2

P(x) 1/6 1/6 1/6 1/2

x 10 7 4 0

Expectwd value ; E(x)

Σx*p(x) = (1/6 * 10) + (1/6 * 7) + (1/6 * 4) + (1/2 * 0)

E(x) = 3.50

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step-by-step explanation:

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )