ВС 2. In ATVW if VW is three meters longer than TV, TW
is 19 meters shorter than the sum of VW and TV,
and the perimeter of ATVW is 62 meters, find the length of VW.
20.75 m
15.75 m
25.5 m
21.75 m
None of the above

9514 1404 393

  21.75 m

Step-by-step explanation:

The given relations tell us that ...

  VW = TV +3

  TW = VW +TV -19

  VW +TW +TV = 62

__

Solving the first equation for TW gives ...

 TV = VW -3

Substituting that into the second equation gives ...

  TW = 2VW -22

And using these expressions in the third equation, we have ...

  VW +(2VW -22) +(VW -3) = 62

  4VW = 87 . . . . . . . . collect terms

  VW = 21.75 . . . . . . divide by 4

The length of VW is 21.75 meters.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)