. If 2n - 5m + 10 = 0, find
i) m, when n=2 ii) n, when m=5​

when n = 2; m = 2

when m=5;   n =

Step-by-step explanation:

2n - 5m + 10 = 0

             -10     -10

2n - 5m = -10

2(2) - 5m = -10

 4 - 5m = -10

 -4            -4

      -5m = -14

        -5       -5

           m = 2

2n - 5(5) = -10

2n - 25 = -10

    +25     +25

2n = 15

2        2

   n =

step-by-step explanation:

do you have a copy of the table?

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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