The number of accidents in a factory for each month is provided: Jan Feb Mar Apr May June July Aug Sep Oct Nov Dec 25 28 24 18 17 27 9 18 22 14 12 26 Which hypothesis test would be appropriate for determining whether some months have a greater number of accidents than others

Chisquare goodness of fit test

Step-by-step explanation:

Given the data:

Jan Feb Mar Apr May June July Aug Sep Oct Nov Dec 25 28 24 18 17 27 9 18 22 14 12 26

The Chisquare goodness of fit test is used to test the relationship between the observed and theoretical or expected model data. Here, we make and assumption about the population using the sample distribution. For the goodness of fit test, there is only one observed variable, here it is the number of factory accident. The null hypothesis is of the claim that the number of factory accidents per month is the same for each month ;

Null hypothesis : Number of factory accident each month is the same ; while the alternative hypothesis is tests that some month gave greater number of accidents, that is ; the number of factory accidents is not the same for each month.

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

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