How do i write a polynomial functions that has roots 3 and 7

Step-by-step explanation:

x^2 - (a+b)x + ab = 0

here, a = 3 and b = 7

hence,

x^2 - (10x) + 21 = 0

lastly , the quadratic equation is

x^2 - 10x + 21 = 0

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: