Find the probability as a percent. You flip a coin and toss a 1-6 number cube. P(not heads and not 6)

Step-by-step explanation:

Gonna give this my best shot at explaining.

So we know that the probability for flipping a coin is 50/50 because it has two sides. So the probablility here is 1/2. (I'm using fractions to make it easier.)

On a dice it has 6 sides, so the probability of rolling 1-to-6 is 1/6.

Since the probability we are trying to calculate here is not getting heads and not getting a 6. We are left with 1/2 for the coin and 5/6 for the dice.

1/2 is removed from the coin since we don't need the heads.

And 1/6 is removed from the dice since we don't need a 6.

Therefore 1/2 mulitplied by 5/6 = 5/12

The percentage is provided at the top.

can someone answer this question plz

step-by-step explanation: