Which one of the following compound inequalities has no solution? (Photo included) 03(x - 1) > 4(x - 2) and 2(x + 2) <(or equal too) 5(x - 1)

– 2x + 5 > (or equal to) - 3x – 2 and - 3x – 2 > - 2x + 4

7x – 8 > 9(x - 1) and 3x + 2 < 5x + 3

- 2x + 5 < - 3x – 3 and - 4x +9 >(or equal to)– 5x + 2

Which equation represents the line that passes through the points and (4, 10) and (2, 7)? y = 3/2x - 11y = 3/2x +4y = - 3/2x + 19y = - 3/2x + 16

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

What is the equation of a vertical line passing through the point (−5, −1)? y = −5 y = −1 x = −5 x = −1