In the straightedge and compass construction of the angle bisector below, which of the following reasons can you use to prove that DBG ZEBG?
BO
O A. BD BE because they are radii of the same circle, DG EG
because they are sides of the equilateral triangle DEG, and
BG BG by the reflexive property. Therefore, BDG sa BEG by AAS
and Z DBG EBG by CPCTC.
B. BD BE because they are radii of the same circle, DG EG
because they are sides of the equilateral triangle DEG, and
TLER
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