What is the solution to the system of equations

x=4 and y=−2

Step-by-step explanation:

Let's solve your system by substitution.

3x+8y=−4;2x−4y=16

Step: Solve 3x+8y=−4 for x:

3x+8y=−4

3x+8y+−8y=−4+−8y(Add -8y to both sides)

3x=−8y−4

3x/3=−8y−4/3 (Divide both sides by 3)

x=−8/3y+−4/3

Step: Substitute −8/3y+−4/3 for x in 2x−4y=16:

2x−4y=16

2(−8/3y+−4/3)−4y=16

−28/3y+−8/3=16 (Simplify both sides of the equation)

−28/3y+−8/3+8/3=16+8/3 (Add 8/3 to both sides)

−28/3y=56/3

−28/3y/−28/3=56/3/−28/3 (Divide both sides by (-28)/3)

y=−2

Step: Substitute−2 for y in x=−8/3y+−4/3:

x=−8/3y+−4/3

x=−8/3(−2)+−4/3

x=4 (Simplify both sides of the equation)

So the Answers are: x=4 and y=−2 or u can switch it around y=−2 and x=4

cosine

step-by-step explanation: