I need help and it would be great if someone could answer most of them please

Step-by-step explanation:

All of the triangles in this problem are right triangles. This means that all of them contain a right angle, this is indicated by the box around one of the angles. The Pythagorean theorem is a property of the sides of a right triangle, this property, in the form of an equation, is as follows,

Where (a) and (b) are the legs, that is, the sides that are adjacent to the right angle of a right triangle. The parameter (c) represents the hypotenuse, the side opposite the right angle of a right triangle. For each triangle, substitute the given side lengths, simplify, and solve for the unknown side.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.