A 35-kg trunk is dragged 10 m up a ramp inclined at an angle of 12 degrees to the horizontal by a force of 90 N applied at an angle of 20 degrees to the ramp. At the top of the ramp, the trunk is dragged horizontally another 15 m by the same force. Find the total work done.

The total work done is approximately 2,114.308 J

Step-by-step explanation:

The mass of the trunk = 35 kg

The height to which the trunk is dragged, d₁ = 10 m

The inclination of the plane on which the trunk is dragged = 12°

The applied force F = 90 N

The angle of inclination of the force to the ramp = 20°

The distance the trunk is dragged horizontally at the top of the ramp, d₂ = 15 m

Work = Force × Distance

The work done along the inclined plane, W₁ = 90 N × cos(20°) × 10 m ≈ 845.723 J

The work done along the horizontal, W₂ = 90 N × cos(20°) × 15 m ≈ 1,268.585 J

The total work done, W = W₁ + W₂

∴ W = 845.723 J + 1,268.585 J = 2,114.308 J

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

answer: (-6,3)

step-by-step explanation: