What is the equation of the line that is parallel to the given line and passes through the point (–2, 2)? Given line: y=1/5x-3

y = 1/5 x + 12/5

Step-by-step explanation:

We are looking for the equation of a line.

We satart with the slope-intercept form of the equation of a line.

y = mx + b

We need to find m, the slope, and b, the y-intercept.

The given line is y = 1/5 x - 3.

Its slope is 1/5.

Parallel lines have equal slopes, so the slope we need is also 1/5.

Now we have for our line

y = 1/5 x + b

Now we find b.

We are given a point on the line, (-2, 2). Using the slope we already know, plug in (-2, 2) in the equation and solve for b.

2 = 1/5 * (-2) + b

10 = -2 + 5b

12 = 5b

b = 12/5

Now that we know the y-intercept, we can write the equation of the line.

y = 1/5 x + 12/5