John bought 8 birds and 6 pigeons for $2400. If he had bought 1 more pigeon and 2 fewer birds, he would have paid $200 more. What is the cost for 1 love bird and 1 pigeon?

1 pigeon is $320

1 love bird is $80

Step-by-step explanation:

Let the cost for 1 love bird be represented by x

Let the cost for 1 pigeon be represented by y.

Since John bought 8 birds and 6 pigeons for $2400. This will be:

8x + 6y = 2400 i

If he had bought 1 more pigeon and 2 fewer birds, he would have paid $200 more. This will be:

6x + 7y = 2600 ii

8x + 6y = 2400 i

6x + 7y = 2600 ii

Multiply equation i by 6

Multiply equation ii by 8

48x + 36y = 14400 iii

48x + 56y = 20800 iv

Subtract iii from iv

20y = 6400

y = 6400/20

y = 320

1 pigeon is $320

From equation i

8x + 6y = 2400

8x + 6(320) = 2400

8x + 1920 = 2400

8x = 2400 - 1920

8x = 480

x = 480/8

x = 60

1 love bird is $80

the first dot plot best represents the data

plzplzplzplz mark brainliest and have a good day

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: