If the mean number of years between asbestos exposure and death is found to be 25 years with a standard deviation of 7 years in a particular county, what is the probability that the mean number of years between asbestos exposure and death will be between 22 and 29 years in a sample of 50 people taken from that community

0.9988 = 99.88% probability that the mean number of years between asbestos exposure and death will be between 22 and 29 years.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean number of years between asbestos exposure and death is found to be 25 years with a standard deviation of 7 years in a particular county

This means that

Sample of 50:

This means that

What is the probability that the mean number of years between asbestos exposure and death will be between 22 and 29 years?

This is the p-value of Z when X = 29 subtracted by the p-value of Z when X = 22.

X = 29

By the Central Limit Theorem

has a p-value of 1.

X = 22

has a p-value of 0.0012.

1 - 0.0012 = 0.9988

0.9988 = 99.88% probability that the mean number of years between asbestos exposure and death will be between 22 and 29 years.

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