The temperature T of a given mass of gas varies inversely with its volume V. The temperature of 90 cm^3 of a certain gas is 25°C. What will the temperature of the gas be when it is compressed to a volume of 20 cm^3? a. 112.5°C
b. 6°C
c. 54°C
d. 120°C

A. 112.5°C

Step-by-step explanation:

Use the inverse variation equation, y =

Replace y with T, and replace x with V:

T =

Plug in 90 as T and 25 as V, then solve for k:

T =

90 =

2250 = k

So, the equation is T =

Plug in 20 as V and solve for T:

T =

T =

T = 112.5

So, the temperature will be A. 112.5°C

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²