Acellus Find the probability that a randomly
selected point within the circle falls
in the red shaded area (square).
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r = 4 cm
4 √2 cm
[?]%
Round to the nearest tenth of a percent.
Enter

The Probability is 63.7%

Step-by-step explanation:

We need to calculate the area of the circle and the area of the square

From the question, we can see that the square is of side 4 √2 cm

The area of the square is simply the square of its side length

We have this as 4√2 * 4√2 = 16 * 2 = 32 cm^2

The area of the circle can be calculated using the formula for the area of a circle, with the radius being 4 cm

So, we have the area of the circle as;

Pi * r^2

= 22/7 * 4 * 4 = 50.3 cm^2

so, to find the probability, we need to divide the area of the circle by the area of the square

we have this as;

32/50.3 = 0.6366

In percentage, we simply multiply by 100% to give

0.6366 * 100% = 63.66%

To the nearest tenth, this is 63.7%

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

f(x)=2/3x-8, which give g(x) the greatest value.

step-by-step explanation: