A company that manufactures vehicle trailers estimates that the monthly profit for selling its midsize trailer is represented by function p, where t is the number of trailers sold. p(t)= -25t^3+635t^2-2500tUse the key features of function p to complete these statements. The company makes a profit when it sells trailers. The maximum profit of approximately $ occurs when it sells approximately trailers.

The answer is below

Step-by-step explanation:

The profit equation is given by:

p(t)= -25t³+625t²-2500t

The maximum profit is the maximum profit that can be gotten from selling t trailers. The maximum profit is at point p'(t) = 0. Hence:

p'(t) = -75t² + 1250t - 2500

-75t² + 1250t - 2500 = 0

t = 2.3 and t = 14.3

Therefore t = 3 trailers and t = 15 trailers

p(15) = -25(15³) + 625(15²) - 2500(15) = 18750

Therefore the company makes a maximum profit of approximately $18750 when it sells approximately 15 trailers.

See below

Step-by-step explanation:

Since t is number of trailers, the domain includes only those values greater than 0.

On the relevant domain, the graph crosses the x-axis at the points (5,0) and (20,0). Between these points, the value of p(t) is positive. So the company makes a profit when it sells between 5 and 20 trailers.

On the positive interval between these points, the graph reaches a relative maximum when t roughly equals 14 and p(t) roughly equals $19,000.

So the maximum profit of approximately $19,000 occurs when it sells approximately 14 trailers.

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d