A $7,000 principal is invested in two accounts, one earning 1% interest and another earning 5% interest. If the total interest for the year is $202, then how much is invested
in each account?
$
at 1% interest
$
at 5% interest

9514 1404 393

Step-by-step explanation:

For "mixture" problems, I like to let the variable represent the amount of the largest contributor. Here, we can let x represent the amount invested at 5%. Then the amount invested at 1% is (7000-x). The total interest earned is ...

  0.05x +0.01(7000 -x) = 202

  0.04x = 132 . . . . . . . . simplify, subtract 70

  x = 3300

  (7000 -x) = 7000 -3300 = 3700 . . . . at 1%

$3700 was invested at 1% interest.

$3300 was invested at 5% interest.

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2