Cho ánh xạ tuyến tính 3 3 f : ℝ ℝ → và hai cơ sở của 3 ℝ : B b b n b = = = − = { 1 2 3 (1,3,3), ( ,6,5), (1,2,2)} , C c = − {c n c 1 2 3 = = = ( ), ( ), ( ) 2, 3,3 5, 1, 5 − + − − 1,0,1 } . Biết: 1 f b( ) ( 5,6,4) = − , 2 f b( ) ( 8,5,2) = − , 3 f b( ) ( 9, 2, 5) = − − − . a. Tìm ma trận 3 [ ] A f E = , từ đó suy ra biểu thức của 1 2 3 f x x x ( , , ).

you going to fail stop

step-by-step explanation:

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.