A ball is launched straight up in the air from a height of 6 feet. Its velocity​ (feet/second) t seconds after launch is given by f(t)= -34t+291. Between 1 second and 8 seconds, the​ ball's height changed by ... feet.
​(Round answer to the nearest​ tenth.)

966 feet

Step-by-step explanation:

First, we can see that we have the velocity function given, a base value for the height, and need to figure out the change in height. We also know that velocity is the derivative of position/height. Thus, we can find the integral of the velocity to find an equation for the height.

Use the exponent rule to turn -34t into -17t² and 291 into 291t to get our result as

-17t²+291t + C = height (h)

When t=0, we know that our height (h) is 6, so C = 6, making our equation

-17t²+291t + 6

To find the change between 1 second and 8 seconds, we can plug 1 and 8 in for t, and find the difference between those values, which is

(-17(8)²+291(8) + 6) - ( -17(1)²+291(1) + 6 )

= 1246 - 280

= 966

Note that we did final value (t = 8) - initial value (t=1), not the other way around

The change in height, between 1 second and 8 seconds, is therefore 966 feet

i am unable to solve this problem

step-by-step explanation:

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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