You are making your schedule for next semester. You have 14 choices for your math class, 12 choices for your English class, 7 choices for your communications class, and 6 choices for your elective. How many different schedules are
possible?
There are
different schedules possible

asking how many combinations are possible is answered by the following expression:

the first step alone offers 14 choices, the second step offers 12 choices. so with these two choices alone there can be 168 different scenarios to choose one from. we just need to keep multiplying for the number of choices we got at each decision to get the number of possible outcomes/configurations

that is

7056

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !