Someone please explain this question PART "b) i" ONLY!!!

This is because we have a list of perfect squares 0,1,4,9,...

We use n-1 in place of n because we're shifting things one spot to the left, since we start at 0 instead of 1.

In other words, if the answer was n^2, then the first term would be 1^2 = 1, the second term would be 2^2 = 4, and so on. But again, we started with 0^2 = 0, so that's why we need the n-1 shift.

You can confirm this is the case by plugging n = 1 into (n-1)^2 and you should find the result is 0^2 = 0. Similarly, if you tried n = 2, you should get 1^2 = 1, and so on. It appears you already wrote the answer when you wrote "Mark Scheme".

All of this only applies to sequence A.

side note: n is some positive whole number.

table 3 represents a direct variation function. : )