Suman and Narayan riding bikes towards each other they are 480 Km apart. The speed of Narayan is 6km/hr faster than Suman. If both meet each other after 6hours find there speeds when both started at same time.​

Suman 37 km/hr

Narayan 43 km/hr

(extremely sorry if this is wrong!!)

Step-by-step explanation:

We can use the formula distance divided by time is speed.

480/6 = 80.

Their speeds must add up to 80 km/hour

Lets set suman as a variable, lets say s.

Narayan has a speed 6 more than suman so we say 6+s

6+s+s = 80

subtract 6 from both sides

s+s = 74

add like terms

s+s = 2s

2s = 74

divide both sides by 2.

74/2=37

s=37

Suman's speed is 37 km/hr.

Narayan's speed would be 6 more than Suman's so we do 6+37

which makes 43 km/hr

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

they disappear if your absent from to long. i found out that the hard way.

step-by-step explanation:

brainliest lol i just need one more brainliest.